sertai langkah langkah.
1
[tex]3 \sqrt{12} + 2 \sqrt{3} = 3 \sqrt{4 \times 3} + 2 \sqrt{3} \\ = (3 \times 2 \sqrt{3} ) + 2 \sqrt{3} \\ = 6 \sqrt{3} + 2 \sqrt{3} \\ = 8 \sqrt{3} \\ [/tex]
2
[tex]3 \sqrt{2} + 5 \sqrt{8} - \sqrt{32} \\ = 3 \sqrt{2} +5 \sqrt{4 \times 2} - \sqrt{16 \times 2} \\ = 3 \sqrt{2} + (5 \times 2) \sqrt{2} - 4 \sqrt{2} \\ = 3 \sqrt{2} + 10 \sqrt{2} - 4 \sqrt{2} \\ = 9 \sqrt{2} [/tex]
3
[tex](2 \sqrt{5} + 3 \sqrt{7} )( 3\sqrt{5} - 2 \sqrt{7} ) \\ = (6 \times 5) + ( - 4 \sqrt{35} ) + (9 \sqrt{35}) + ( - 6 \times 7) \\ = 30- 4 \sqrt{35} + 9 \sqrt{35} - 42 \\ = - 12 + 5 \sqrt{35} [/tex]
Jawaban:
3√12 + 2√3
3√4.√3 + 2√3
6√3 + 2√3
8√3
....
3√2 + √8 - √32
3√2 + √4.√2 - √16.√2
3√2 + 2√2 - 4√2
√2
......
(2√5 + 3√7) (3√5 - 2√7)
2√5(3√5 - 2√7) + 3√7(3√5 - 2√7)
30 - 4√35 + 9√35 - 42
5√35 - 12
[answer.2.content]
